Differentials Again Again

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On reflection, I think I prefer this version of the “theorem”:

Theorem: Any twice differentiable function of one variable has a second derivative vanishing everywhere.

Proof: y''/y'2 = (d2y/dx2)/(dy/dx)2 = (d2y/dx2) (dx/dy)2 ... etc.

Issa bottle a wine.

Comments

  1. Anonymous10:15 AM

    I don't entirely understand your typographic representation. What is y''/y'2 ? Is it the second derivative over the (first derivative squared)?

    ReplyDelete
  2. Wabulon2:32 PM

    Yes. I could probably hustle up superscripts somehow, but I'm too lazy to try to learn how.

    ReplyDelete

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